Below are instructions for using Excel to perform a T-test on data.
Excel will return a probability value for you. If the number is < .05, then there is a statistically significant failure of the data to support the null hypothesis (Normal > ephedrine-treated), so you may accept the alternate hypothesis (Normal < ephedrine-treated). Otherwise, accept the null hypothesis.
|
A |
B |
|
|
1 |
Normal |
Ephedrine |
|
2 |
85 |
102 |
|
3 |
97 |
114 |
|
4 |
86 |
121 |
|
5 |
104 |
108 |
|
6 |
0.024886 |
If you prefer to have Excel calculate metabolic rate for you, the set up below works well. In Cell J3 (note two narrow columns put in for separators), I put the following formula:
=15/B3*273/(273+C3)*734/760*3600*4.8*10/(0.437+(2.143*D3))
B3 is the datum for seconds
C3 is temperature
D3 is weight
I then clicked on cell J3 and drug down to J10 and selected "Fill" and "Down" from the "Edit" menu. I built a similar formula in K3:K10 referring to the proper cells in the formula. I used the average function in Cells J11 and K11, the standard Deviation function in J and K 12 and the T-test function in K 14 as described above.
|
Normal |
Ephedrine |
Metabolic Rate |
||||||||
|
Group |
Total sec for 15 mL |
T °C |
Wt (g) |
Total sec for 15 mL |
T °C |
Wt (g) |
N |
E |
||
|
1 |
1182 |
26 |
21.2 |
|||||||
|
2 |
551 |
25 |
24 |
591 |
25 |
23.8 |
||||
|
3 |
479 |
26 |
24.2 |
637 |
26 |
11.1 |
||||
|
4 |
411 |
26 |
28 |
532 |
26 |
21.6 |
||||
|
5 |
630 |
25 |
26.5 |
688 |
26 |
21 |
||||
|
6 |
662 |
25 |
21.6 |
738 |
25 |
23.6 |
||||
|
7 |
474 |
26 |
32 |
620 |
26 |
24 |
||||
|
8 |
609 |
26 |
20.6 |
907 |
26 |
13.5 |
||||
|
MEAN |
||||||||||
|
SD |
||||||||||
|
SE |
2.4 |
2.3 |
||||||||
|
p |
0.47760 |
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